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Find a round to the nearest tenth 12 22 75 x x=?
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Find a round to the nearest tenth 12 22 75 x x=?

Find a round to the nearest tenth 12 22 75 x x=?-example-1
User Martin Kouba
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1 Answer

7 votes

Answer:

By law of Sines


(Sin75^o)/(22) =(Sinx)/(12)


  • (Sin75)/(22)(12)=(Sinx)/(12) (12)

  • 0.5268=Sinx

  • Sin^(0.5268)=x

  • x=31.789

  • x=31.79^o

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hope it helps..

have a great day!!

User MowDownJoe
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