Question

Find a round to the nearest tenth 12 22 75 x x=?

Answer 1

By law of Sines

`(Sin75^o)/(22) =(Sinx)/(12)`

• 
  `(Sin75)/(22)(12)=(Sinx)/(12) (12)`

• 
  `0.5268=Sinx`

• 
  `Sin^(0.5268)=x`

• 
  `x=31.789`

• 
  `x=31.79^o`

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