Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second.

y=-16x^2+239x+127

Answer 1

7.47 seconds

Explanation:

From the quadratic equation the x coordinate of the vertex is

x = -b/(2a)

---------------------------

y = -16x² + 239x + 127

x = -239/ ( 2 * (-16) )

x = -239 / (-32)

x = 7.46875

Rounded

x = 7.47