Question

100 POINT PLEASE HELP QUICK!!!!

Answer 1

`adjacent = \sqrt{ {50}^(2) - {14}^(2) } = 48 \\ \\ \sin(Q) = (14)/(50) = (7)/(25) \\ \cos(Q) = (48)/(50) = (24)/(25) \\ \tan(Q) = (14)/(48) = (7)/(24)`

`\sin(R) = (48)/(50) = (24)/(25) \\ \cos(R) = (14)/(50) = (7)/(25) \\ \tan(R) = (48)/(14) = (24)/(7)`

Answer 2

Base

• √50²-14²
• √2500-196
• √48²
• 48

Now

• sinQ=P/H=14/50
• cosQ=B/H=48/50
• tanQ=P/B=14/48
• cotQ=B/P=48/14
• secQ=H/B=50/48
• cosecQ=H/P=50/14