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A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill. there is no friction, what is the maximum vertical height the person in the cart can reach?

User Xinan
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1 Answer

2 votes

Answer:

the maximum vertical height the person in the cart can reach is 18.42 m

Step-by-step explanation:

Given;

mass of the person in cart, m₁ = 45 kg

mass of the cart, m₂ = 43 kg

acceleration due to gravity, g = 9.8 m/s²

final speed of the cart before it goes up the hill, v = 19 m/s

Apply the principle of conservation of energy;


mgh_(max) = (1)/(2)mv^2_(max)\\\\ gh_(max) = (1)/(2)v^2_(max)\\\\h_(max) = (v^2_(max))/(2g) \\\\h_(max) =((19)^2)/(2* 9.8) \\\\h_(max) = 18.42 \ m

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m

User Blero
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