Question

Factorise fully 16c^4p^2+20cp^3​

Answer 1

Explanation:

16c^4p^2 + 20cp^3

take common

=4cp^2(4c^3 + 5p)

Answer 2

Given the expression below:

`\large \boxed{16 {c}^(4) {p}^(2) + 20c {p}^(3) }`

We can factor out c-term, p² and 4 (from 16 and 20)

`\large{4c {p}^(2) (4 {c}^(3) + 5p)}`

Answer

• 4cp²(4c³+5p)