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An electron in a hydrogen atom drops from the n= 3

energy level to the n=2 energy level. The energy of
the emitted photon is
A) 1.89 eV
C) 1.51 eV
B) 3.40 eV
D) 4.91 eV

1 Answer

4 votes

Answer: D) 4.91 eV

Step-by-step explanation:

User Atereshkov
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