Answer:
2) 40
Explanation:
the perimeter of Rhombus =
4 × (√(12/2)²+(16/2)² )
= 4× (√6²+8²)
= 4× (√100)
= 4×10
= 40
Q) 4 × (√(12/2)²+(16/2)² )
→ 4 × (√6²+8²)
→ 4 × (√100)
→ 4 × 10
→ 40 is the perimeter of rhombus.
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