Question

Does f(x) = - 3x² + 6x - 4 have a maximum or
minimum? Find the value

Answer 1

Maximum value.

it = -1.

Explanation:

Maximum value as the coefficient of x^2 is negative.

To find this value we convert to vertex form:

y = -3x^2 + 6x - 4

y = -3(x^2 - 2x) - 4

y = -3[(x - 1)^2 - 1] - 4

y = -3(x - 1)^2 + 3 - 4

y = =3(x - 1)^2 - 1

Minimum value = -1.