Question

A skier of weight 700 N is pointed down a ski hill that has a slope angle of 25° above horizontal.

What is the component of his weight pulling him down the slope.
O 634N
O 326N
O 296N
O 700N

Answer 1

O 296N

Step-by-step explanation:

F_y = F*sin(x)

F_y = 700N*sin(25°)

F_y = 295.83N or 296N