Question

What is the reduction half-reaction for the equation below?

5Fe2+(aq) + MnO4" (aq) + 8H+(aq) → 5Fe3+ (aq) + Mn2+(aq) +
4H2O(1)

Answer 1

`MnO_4^-+8H^++5e^-\rightarrow Mn^(2+)+4H_2O`

Step-by-step explanation:

Hello there!

In this case, since redox reactions are characterized by the presence of a reduction reaction, whereby the oxidation of the element decreases, and an oxidation reaction whereby the oxidation of the element increases.

In such a way, for the given chemical equation, we can see Fe is increasing its oxidation state from 2+ to 3+, which means it is oxidized. On the flip side, Mn is being reduced from 7+ (MnO₄⁻) to 2+ and this, the reduction half-reaction is:

`MnO_4^-+8H^++5e^-\rightarrow Mn^(2+)+4H_2O`

Whereas five electrons are carried.

Regards!