118k views
19 votes
Find the domain and range. Show solution.


y = (2)/(2x)
Domain:
Range:​

User Sagar Modi
by
8.6k points

1 Answer

6 votes

We are given with a function y =2/(2x) . So , if we cancel the 2 from both numerator and denominator we are left with y = 1/x . Now , here we need to find the domain , bur let's Recall that Domain is the set of all values for which the given function is defined .Now , here , if we put x = 0 , then y will be not defined , but as for domain we need only the set of values for which the function is defined , so domain willn't include 0 , and for all real numbers except 0 , the given function is defined . So Our domain is
{\boxed{\bf{(-\infty,0)\cup (0,\infty)}}} and as this interval contains all real numbers except 0 , so domain can be further written as
{\boxed{\mathbb{R}-\bf \{0\}}} . Now , Range is the set of all output values of the function when we put the values of domain as input . So , now here when we put values of domain as input like let's put x = -1 , -2 , -3 , -4 , 1 , 2 , 3 ,..... we will get y = -1 , -1/2 , -1/3 , -1/4 , 1 , 1/2 , 1/3 and so on , now , the input will give output as 0 , iff input is Infinite , but as input can never be infinite, so output will never comes to 0 as the intervals of real numbers is
{\bf{(-\infty,\infty)}} it's an open interval so Infinity and -ve infinity is not concluded in the above interval because whenever we think a number as large as much we can think , their exists infinitely large numbers greater than it , assume you're thinking 10¹⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰ as the largest number you can think , but if we add 1 in that i.e 10¹⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰⁰ + 1 comes to be greater than it , Hence , we don't include Infinity and -ve Infinity in the interval which represents the set of all real numbers. So now the range is same as the Domain i.e
{\boxed{\bf{(-\infty,0)\cup (0,\infty)}}} or
{\boxed{\mathbb{R}-\bf \{0\}}}

Hence , we concluded that :


  • {\bf Domain=\mathbb{R}-\bf \{0\}}

  • {\bf Range=\mathbb{R}-\bf \{0\}}
  • Range = Domain
User Royi
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories