Answer:
Explanation:
1) Step 4: Marc has converted radical form to exponent form
Step 5: He has evaluated the value of the radical
3)
![x = \sqrt[3]{8}](https://img.qammunity.org/2022/formulas/mathematics/college/j7tlcc36eyyy4l0y8v15gdflhn1w4rbps9.png)
Here, 3 is index and 8 is radicand.
Prime factorize 8 and for every 3 numbers we can take one number outside the radical
Solution:
![x = \sqrt[3]{2*2*2}\\\\x = 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/axsx52erpnu1xukdc7k376nsfvkep7ytbt.png)
4) No,my equation does not have an extraneous solution.
My solution, satisfies the equation