Question

A square has a perimeter of 16 units and an area of 16 square units. What is the side length of the square? Show your work.

Answer 1

Explanation:

that r = P/(2π) so A = π(P/(2π))2 = P2/(4π). Any positive area less than this is also possible. So in this problem the largest area possible is (16 in.)2/(4π) = 64/π sq.

Answer 2

4 units

Explanation:

according to question:

perimeter of square = 16 units

4a = 16

where a is the side length

a = 16/4

= 4 units