Question

Given that cot(θ)= -√5/3 and cos(θ) < 0, find sin(θ)

Answer 1

D. 3√14 /14

Explanation:

given that cot(θ)= -√5/3 and cos(θ) < 0

cot(θ)= -√5/3 and cos(θ) < 0, the angle should be on quadrant II.

cot(θ)= -√5/3 => x = -√5 , y = 3

h = √(-3)²+5 =√14

so, sin(θ) = y/h = 3/√14 = 3√14 /14