Question

An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the

substance absorbed 5895 J of energy. What is the specific heat of the substance?

A. 5895 J/(g*C)
B. 4.18 J/(g*C)
C. 4.84 J/( g*C)
D. O.06 J/(g*C)

Answer 1

A. 5895 J/g*C)

Step-by-step explanation:

An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the substance absorbed 5895 J of energy.