Question

Let p(x)=4x-18 and q(x)=-2x+k. For what value of k will the x intercept of q(x) be equivalent to the x intercept of p(x)

Answer 1

Explanation:

The x-intercept of a line exists where y = 0. So first we will set each of those lines = 0:

4x - 18 = 0 and -2x + k = 0. In order for the x-intercepts to be equal, we have to solve each equation for x and then set those expressions equal to each other.

4x = 18 so

x = 9/2.

-2x = -k so

x = k/2. If the x-intercepts are the same value, then

`(9)/(2)=(k)/(2)` so, obviously,

k = 9