Question

Write the log equation as an exponential equation. You do not need to solve for x. \log_9\left(2\right)=2x-1 log 9 ​ (2)=2x−1

Answer 1

`9^(2x-1) = 2\\`

Explanation:

According to the law of logarithm;

`If \ log_ab = x\\a^x = b`

Given

`\log_9\left(2\right)=2x-1`

Comparing with the original expression;

a = 9, b = 2 and c = 2x - 1

Substitute into the result indicinal expression;

`9^(2x-1) = 2\\`

This gives the required exponential equation