Answer:
80.7 °C
Step-by-step explanation:
Step 1: Given and required data
- Mass of water (m): 20.0 g
- Initial temperature (T₁): 95.0 °C
- Heat released (Q): -1,200 J (the negative sign is due to it being released)
- Specific heat capacity of water (c): 4.184 J/g.°C
Step 2: Calculate the final temperature of the water
We will use the following expression.
Q = c × m × (T₂ - T₁)
T₂ = Q / c × m + T₁
T₂ = -1,200 J / (4.184 J/g.°C) × 20.0 g + 95.0 °C = 80.7 °C