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Please help me with this math

Please help me with this math
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2 votes
Please help me with this math

Please help me with this math-example-1
User Naster
by
8.8k points

1 Answer

4 votes

Answer:

(E) 9

Explanation:


((3^(2008))^2-(3^(2006))^2)/((3^(2007))^2-(3^(2005))^2) = \\((3^(2007+1))^2-(3^(2007-1))^2)/((3^(2007))^2-(3^(2007-2))^2) = \\((3^(2007))^2(3^(2)-3^(-2) ))/((3^(2007))^2(1-3^(-4) )) =\\(9-(1)/(9) )/(1-(1)/(81) )=\\(80)/(9):(80)/(81) = \\(80)/(9)*(81)/(80) = (81)/(9) = 9

User Jose Ospina
by
8.3k points
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