Question

Please help me with this math

Answer 1

(E) 9

Explanation:

`((3^(2008))^2-(3^(2006))^2)/((3^(2007))^2-(3^(2005))^2) = \\((3^(2007+1))^2-(3^(2007-1))^2)/((3^(2007))^2-(3^(2007-2))^2) = \\((3^(2007))^2(3^(2)-3^(-2) ))/((3^(2007))^2(1-3^(-4) )) =\\(9-(1)/(9) )/(1-(1)/(81) )=\\(80)/(9):(80)/(81) = \\(80)/(9)*(81)/(80) = (81)/(9) = 9`