Answer: 9 < √97 < 10
=====================================================
Step-by-step explanation:
Consider that 81 < 97 < 100 is a true statement. Note the 81 and 100 are perfect squares such that 81 = 9^2 and 100 = 10^2
We can apply the square root to all three sides to get the following
![81 < 97 < 100\\\\√(81) < √(97) < √(100)\\\\√(9^2) < √(97) < √(10^2)\\\\9 < √(97) < 10\\\\\text{The number }√(97) \text{ is between 9 and 10}\\\\](https://img.qammunity.org/2022/formulas/mathematics/high-school/2w8kb0sdqf62n2u64beupa4r9r0mxfyabl.png)
Using a calculator, we can help verify this
![√(97) \approx 9.85](https://img.qammunity.org/2022/formulas/mathematics/high-school/8fink9pm96ty7x6gjurbz1xl6sd2ju5vri.png)