Question

Graph a line that contains the point (-6,1) and has a slope of 5

Answer 1

Explanation:

Equation of a line passing through a point (h, k) and slope 'm' is given by,

y - h = m(x - k)

Equation of a line passing through (-6, 1) and slope = 5,

y - 1 = 5(x + 6)

y = 5x + 31

Input-output values of the given equation,

x -6 -4 -2 0

y 1 11 21 31

Now plot these points on a graph.