If (a/b) =(9/7)^-3 ÷(3/7)^1, then find the value of (a/b)^2

asked Dec 14, 2022 89.9k views

5 votes

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4 votes

Answer:

decimal = 1.20527

Explanation:

(a)/(b) = ((9)/(7))^(-3) / ((3)/(7))^1

$=((7)/(9))^3 * (7)/(3)\\\\$

$((a)/(b))^2 = (((7)/(9))^3)^2 * ((7)/(3))^2\\\\$

$= (7^6 * 7^2)/(9^6 * 3^2)\\\\= (7^8)/(9^6 * 9)\\\\=(7^8)/(9^7)\\\\=(7^7 * 7)/(9^7)\\\\= 7 * (7^7)/(9^7)\\\\= 7 * ((7)/(9))^7$

=(5764801)/(4782969)

Justus Grunow answered Dec 17, 2022

4.8k points

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