Question

(PRECALC) I need help on this one plz ❤️❤️❤️ help a girl out & the favor will be returned

Answer 1

The coordinates of the P' point are (-17.3,-10).

Explanation:

We can use the components of the vector from 0 to P point. We know that the diameter is 40 meters, so the magnitude of the vector will be 20 m.

Now, the angle from the negative x-direction to the vector is 210°-180° = 30°.

The x-component of the vector will be:

`V_(x)=-Vcos(30)`

`V_(x)=-20cos(30)=-17.32\: m`

It is negative because the component is in the negative x-direction.

The y-component of the vector will be:

`V_(y)=-Vsin(30)`

`V_(y)=-20sin(30)=-10\: m`

It is negative too because the component is in the negative y-direction.

Therefore, the coordinates of the P' point are P'(-17.3,-10)

I hope it helps you!