Question

Find the magnitude of the vector that begins at (1,1) and ends at (-8,12).

a. 15.81
b. 14.76
c. 14.21
d.04

Answer 1

The correct answer is C (14.21)

Step-by-step explanation:

(We can use the Distance Formula to find a vector’s magnitude)

Let (x1, y1) be (1, 1) and (x2, y2) be (-8, 12)

Distance
= sqrt((x2 - x1)^2 + (y2 - y1)^2)
= sqrt((- 8 - 1)^2 + (12 - 1)^2)
= sqrt((-9)^2 + 11^2)
= sqrt(81 + 121)
= sqrt(202)
≈ 14.21

Answer 2

Answer the answer is a 15.81

Step-by-step explanation: