Question

Please help!!
Need to get this done

Answer 1

Given:

Segment AD is perpendicular to segment BC.

D is the midpoint of segment BC.

To prove:

`\Delta BDA\cong \Delta CDA`

Solution:

The two column proof is shown below:

Statements Reasons

1.
`\overline{AD}\perp \overline{BC}`, D is the midpoint of
`\overline{BC}` 1. Given

2.
`\overline{BD}\cong \overline{CD}` 2. Definition of midpoint

3.
`m\angle ADB=90^\circ \text{ and }m\angle ADC=90^\circ` 3. Definition of perpendicular lines

4.
`m\angle ADB=m\angle ADC` 4. Substitution

5.
`m\angle ADB\cong m\angle ADC` 5. Definition of congruence

6.
`\overline{AD}\cong \overline{AD}` 6. Reflexive property

7.
`\Delta BDA\cong \Delta CDA` 7. SAS congruence postulate

Hence proved.