line y = − x / 5 + 4 / 5
slope( m1) = -1/5
Slope of required line( m2) = 5
[as it is perpendicular to given eqn of line
m1×m2= -1
m2=1/m1= 5]
y-4= 5(x+3)
y-4=5x+15
y=5x+19
4.4m questions
5.7m answers