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What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?
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3 votes
What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?

User Ali Ahmadi
by
4.9k points

1 Answer

3 votes

V = 99 volts

Step-by-step explanation:

The voltage drop can be calculated using Ohm's law:

V = IR

= (1.10 A)(90 Ω)

= 99 volts

User Lpiepiora
by
4.3k points
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