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Khan academy, law of sines
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Khan academy, law of sines

Khan academy, law of sines-example-1
User Byusa
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1 Answer

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Answer:

m∠B = 76°

Explanation:


(sinB)/(b)=(sinC)/(c)\\\\sinB=(sinC)/(c)(b)\\\\B=sin^(-1)((sin(29))/(9)(18))\\\\B=75.8=76

Therefore, m∠B = 76°.

User Bill Sambrone
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