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Help with khan academy problem, law of sines
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Help with khan academy problem, law of sines

Help with khan academy problem, law of sines-example-1
User Bebosh
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1 Answer

4 votes

Answer:

104°

Explanation:


(sin~B)/(18) =(sin~29)/(9) \\sin~B=(18)/(9) * sin~29\\sin~B=2~sin~29\\B=sin^(-1)(2 ~sin~29)\\=104^\circ

User ITemius
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