Question

What is the equation of the line that is parallel to the given line and passes theought the point (12, -2)

Y= -6/5x + 10
Y= -6/5x + 12
Y= -5/6x - 10
Y= 5/6x - 12

Answer 1

Option D (y = 5/6x -12).

Explanation:

Hey there!

The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].

According to the question, the first line passes through point (12,6) and (0,-4).

So,

`slope(m1) = (y2 - y1)/(x2 - x1)`

`or \: m1 = ( - 4 - 6)/(0 - 12)`

`or \: m1 = (5)/(6)`

Therefore, the slope of the line is 5/6.

Now as per the condition of parallel lines, m1 =m2 = 5/6.

So, keeping the value of m2 in equation (i), we get;

(y+2) = 5/6(x-12)

`y + 2 = (5)/(6) x - 10`

or, y = 5/6x - 12.

Therefore, the required equation is y = 5/6 X - 12.

Hope it helps!