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solve the simultaneous linear algebra quadratic equation 2x-y=8 3x-y=17​

2 Answers

5 votes

Answer:

2x-y=8

(3x-y=17)*_1

2x-y=8

-3x+y=-17

#-x=-9, x=9 & y=-10

User Ashtom
by
3.3k points
1 vote

Answer:

x = 9 and y = 10

Explanation:

Subtract the second equation from 1 as in doing so the y will get cancelled as they are of the opposite sign.

2x - y = 8

-3x + y = -17

-----------------

- x = - 9

Therefore,

x = 9

Now we will add the value of x to any of the equation from the question.

2x - y = 8

2(9) - y = 8

18 - y = 8

Therefore,

y = 10

User Tom Russell
by
3.7k points