Question

Calculate the boiling point of 3.42 m solution of ethylene glycol, C2H602, in water (Kb =0.51°C/m, the normal boiling point of water is 100°C):​

Answer 1

128.10 degree Celsius

Step-by-step explanation:

The boiling point is given by

`T_b = (1000*K_b * w)/(M*W)`

Substituting the given values, we get -

`T_b = (1000*0.51 * 3.42)/(62.07)\\T_b = 28.10`

Tb is the change in temperature

T2 -T1 = 28.10

T2 = 28.10 +100

T2 = 128.10 degree Celsius