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Multiply: (x – 4)(x + 5)

(a) x2 + 5x - 20

(b) x2 - 4x - 20

(c) x2 - x - 20

(d) x2 + x - 20​

User Glts
by
5.2k points

2 Answers

3 votes

FOIL


\mathbb{PROBLEM:}

» Multiply: (x – 4)(x + 5)

  • (a) x² + 5x - 20
  • (b) x² - 4x - 20
  • (c) x² - x - 20
  • (d) + x - 20


\mathbb{ANSWER:}


  • \tt \color{hotpink} \bold{{x}^(2) + x- 20}

— — — — — — — — — —

Solution:


  • \tt \bold{ F} \to (x – 4)(x + 5) = \blue{ {x}^(2) }


  • \tt \bold{O } \to (x – 4)(x + 5) = \blue{ 5x}


  • \tt \bold{ I} \to(x – 4)(x + 5) = \blue{ -4x}


  • \tt \bold{L } \to (x – 4)(x + 5) = \blue{ - 20}

So,


\to \: \tt x {}^(2) + 5x - 4x - 20 \\ \tt \: = \underline{ \boxed{ \purple{ \tt{ {x}^(2) + x - 20 }}}}

Hence, choice D is correct.

_______________❦︎_______________

Multiply: (x – 4)(x + 5) (a) x2 + 5x - 20 (b) x2 - 4x - 20 (c) x2 - x - 20 (d) x2 + x-example-1
User Ethan McTague
by
5.2k points
11 votes

Solution:


\small\bold{(x – 4)(x + 5) }


\small\bold{ → x(x + 5) -4(x + 5) }


\small\bold{→ x2 + 5x – 4x – 20 }


\small\bold{ → x2 + x - 20 }

Option (d) x2 + x - 20 is correct

User Ozturkib
by
5.6k points