Question

An object is launched from the roof of a building 192

feet above the ground. The object's height (in feet)
after t seconds is given by the function
h(t) = -16° +64t + 192
A) What is the height of the object after two-and-a-half
seconds?
252 ft
256 ft
312 ft
620 ft

Answer 1

252 ft



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Answer 2

252 ft

Explanation:

h(t) = -16t^2 +64t + 192

We want to find h when t= 2.5

h(2.5) = -16 (2.5)^2 +64(2.5) +192

=-16(6.25) +160+192

=-100+160+192

=252