Question

The mean amount of sleep needed for adults is 503 minutes per night. If the standard deviation for adult sleepers is [s]. What is the Z score associated with sleeping 503 minutes per night?

Answer 1

Z score associated with sleeping 503 minutes = 0 minutes

Explanation:

Given values of sleep per night for adults:

Mean value X = 503

Standard deviation σ = s

FInd:

Z score associated with sleeping 503 minutes

Computation:

⇒ P[X = 503]

⇒ P[(x - X) / σ] = [503 - 503] / s

⇒ Z score value = [0] / s

⇒ Z score value = 0

Z score associated with sleeping 503 minutes = 0 minutes