Question

The average age of 6 men is 35 years and

the average age of four of them is 32 years.
Find the ages of the remaining two men if
one is 3 years older than the other.​

Answer 1

39.50

42.50

Explanation:

Age of the 2 men = sum of the ages of the 6 men - sum of the ages of the 4 men

Average = sum of ages / total number of men

35 = sum of ages / 6

sum of ages = 35 x6 = 210

32 = sum of ages / 4

32 x 4 = sum of ages

128

210 - 128 = 82

age of the younger man = x

age of the older man = 3 + x

x + 3 + x = 82

2x + 3 = 82

2x = 82 - 3

2x = 79

x = 79/2 = 39.5

older man = 39.5 + 3 = 42.50