Question

The area of a rectangle is 506 square metre. If its length is 23 metre, then find its breadth?

Answer 1

The area of a triangle can be determined with the two side lengths, the length and breadth/width multiplied.

x = unknown value of breadth/width

23 = length

506 = the area of the two lengths multiplied

23(x) = 506

/23 /23

x = 22, 22 metres is it's breadth.

Answer 2

22m is the breadth of the rectangle.

Explanation:

Given:

• Area of Rectangle is 506 m² .
• Length of the Rectangle is 23m.

`\:`

To Find:

• Breadth of the rectangle.

`\:`

Solution:

As, we know,

`{ \boxed{ \pink{Area _((rectangle)) \: = length * breadth}}}`

➝ 506m² = l × b

➝ 506m² = 23 × b

➝ b = 506/23 = 22

Hence, Breadth of the Rectangle is 22m.

`\:`

Check:

Area = length × breadth

➝ 23 × 22

➝ 506m²

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`{ \sf{Additional \: Information}}`

`\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf{ \green{ Formulas\:of\:Areas:-}}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length* Breadth \\\\ \star\sf Triangle=(1)/(2)* Base* Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\frac {1}{2}* d_1* d_2 \\\\ \star\sf Rhombus =\:\frac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base* Height\\\\ \star\sf Trapezium =\frac {1}{2}(a+b)* Height \\ \\ \star\sf Equilateral\:Triangle=\frac {√(3)}{4}(side)^2\end {array}}`