Question

Determine the level in decibels of a sound that has an intensity I = 10^-6 watts/cm2​

Answer 1

The level in decibels is 100.

Explanation:

The intensity level in decibels (β) can be found using the following equation:

`\beta = 10log((I)/(I_(0)))`

Where:

I: is the intensity = 10⁻⁶ W/cm²

I₀: is the reference intensity = 10⁻¹² W/m²

First, we need to convert the unit of the given intensity from W/cm² to W/m².

`I = 10^(-6) (W)/(cm^(2))*((100 cm)^(2))/(1 m^(2)) = 10^(-2) W/m^(2)`

Hence, the level in decibels is:

`\beta = 10log((10 ^(-2) W/m^(2))/(10^(-12) W/m^(2))) = 100 dB`

Therefore, the level in decibels is 100.

I hope it helps you!