Question

Find the magnitude and direction of AB vector joining point A(9,12) and B(8,11)​

Answer 1

Explanation:

x1=9 x2=8 y1=12 y2=11

=x2-x1

y2-y1

=8-91

1-12

=-1

-1

magintude =
`\sqrt{(xcomp)^2+(y comp)^2`

=
`\sqrt{(-1)^2+(-1)^2`

=
`\sqrt{1+1`

=
`\sqrt{2`

direction=y component/x component

tan=-1/-1

tan=1

`tan^(-1)` 1=45

=45 degree

both x component and y component are negative so it lies on third quadrant.