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Is x=2 a root of (2x-3)(3x + 2)(x+2)(x+2)(x-7/8)?
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Is x=2 a root of (2x-3)(3x + 2)(x+2)(x+2)(x-7/8)?

User Edelwater
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1 Answer

3 votes

Answer:

No

Explanation:

2x-3 = 0 so x = 3/2

3x+2 = 0 so x = - 2/3

x+2 = 0 so x=-2 (twice)

x-7/8 = 0 so x=7

User Pazcal
by
4.9k points
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