Question

What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?

Answer 1

Answer: A volume of 500 mL water is required to prepare 0.1 M
`H_(3)PO_(4)` from 100 ml of 0.5 M solution.

Step-by-step explanation:

Given:
`M_(1)` = 0.1 M,
`V_(1)` = ?

`M_(2)` = 0.5 M,
`V_(2)` = 100 mL

Formula used to calculate the volume of water is as follows.

`M_(1)V_(1) = M_(2)V_(2)`

Substitute the values into above formula as follows.

`M_(1)V_(1) = M_(2)V_(2)\\0.1 M * V_(1) = 0.5 M * 100 mL\\V_(1) = 500 mL`

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M
`H_(3)PO_(4)` from 100 ml of 0.5 M solution.