Which equation has the following: Center (0, -3) and radius √(11)

Question

Which equation has the following: Center (0, -3) and radius
`√(11)`

Answer 1

The equation of the circle is
`x^2 + (y + 3)^2 = 11`

Explanation:

Equation of a circle:

The equation of a circle with center
`(x_0,y_0)` and radius r is given by:

`(x - x_0)^2 + (y - y_0)^2 = r^2`

Center (0, -3)

This means that
`x_0 = 0, y_0 = -3`

Radius square root of 11

This means that
`r = √(11)`

Equation of the circle:

`(x - x_0)^2 + (y - y_0)^2 = r^2`

`(x - 0)^2 + (y - (-3))^2 = (√(11))^2`

`x^2 + (y + 3)^2 = 11`

The equation of the circle is
`x^2 + (y + 3)^2 = 11`