How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?

asked Jul 16, 2023 233k views

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7 votes

Answer:

5.98 m

Step-by-step explanation:

$T=2\pi \sqrt(L)/(g)$

$T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2)$ = 11.15*4.6²/(4π²) = 5.98 m

Dennis George answered Jul 19, 2023

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