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How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?​

User Aneroid
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4.8k points

1 Answer

7 votes

Answer:

5.98 m

Step-by-step explanation:


T=2\pi \sqrt(L)/(g)


T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2) = 11.15*4.6²/(4π²) = 5.98 m

User Dennis George
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