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12n^2+12n+9=0
Please solve!

User Kdabir
by
4.1k points

1 Answer

1 vote

Answer:

n = (1/2)(-1 ± i√2)

Explanation:

Among the several ways in which quadratic equations can be solved is the quadratic formula. Putting to use the coefficients {12, 12, 9}, we obtain the discriminant, b^2 - 4ac: 12^2 - 4(12)(9) = 144 - 432 = -288. The negative sign of this discriminant tells us that the quadratic has two unequal, complex roots. These roots are:

-b ± √(discriminant)

n = ---------------------------------

2a

Here we have:

-12 ± √(-288) -12 ± i√2√144 -12 ± i12√2

n = ---------------------- = ------------------------ = --------------------

2(12) 24 24

or:

n = (1/2)(-1 ± i√2)

User Phylliade
by
4.4k points