Question

A car tire with a diameter of 1.6 ft rotates 275 degrees . How far does a point on the circumference of the tire travel

Answer 1

A point on the circumference of the tire will travel 7.68 ft.

Explanation:

Given;

radius of the car tire, r = 1.6 ft

angular distance or rotation = 275⁰

A complete rotation of the tire = 360⁰

the distance a point on the circumference will travel = 2πr

If 360⁰ = 2πr

then 275⁰ = ?

`= (275 \ * \ 2\pi r)/(360) = (275 \ * \ 2\pi * 1.6ft)/(360) = 7.68 \ ft`

Therefore, a point on the circumference of the tire will travel 7.68 ft.