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Write in standard form the equation of a line with a slope of -3/5 and a y intercept of -3

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Answer:

5y+3x=-9

Explanation:

Let us start by the general form of the standard equation, Ax+By=C. One way we can solve this problem is by finding the slope-intercept form of this equation, y=mx+b, and converting it into the standard equation. In the slope-intercept form, m represents the slope, b represents the y intercept.

From this problem, we are given both the slope and the y intercept. We know have the equation:


y=-(3)/(5)x -3

Great! Now let us rearrange the terms so that the y and x terms are on one side of the equation.


y+(3)/(5) x=-3

This seems right, but a standard equation must have coefficient values that are real numbers. So, A and B must be real numbers. We can do this by multiplying the entire equation by 5 and ridding the denominator of the A term.


5y+3x=-9

I hope this helps! Please let me know if you have any questions :)

User Flauwekeul
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