Question

1) Write an equation that is parallel to the line 3x – 2y = 5 and passes through the point (1,2).

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Answer 1

3/2x+1/2

Explanation:

just took on progress learning and was correct:)

Answer 2

The easiest way to find the line parallel to 3x -2y =5 through (1,2), we must set 3x - 2y = 5 into slope-intercept form

`3x-2y =5\\-2y = -3x+5\\y = (3)/(2)x-(5)/(2)`

In slope-intercept form, y = mx + b, m is the slope. For two lines to be parallel, their slopes must be equal.

Thus the new line that is parallel to 3x - 2y = 5 must also have a slope of (3/2)x

`y= (3)/(2) x+b`

To find b, we must plug in (1,2)

`2 = (3)/(2)*1 + b\\b = (1)/(2)`

Thus the equation that is parallel to 3x-2y = 5 and passes through (1,2) is
`y = (3)/(2)x+(1)/(2)`

Hope that helps!