227k views
3 votes
13. Find the vertex of f(x)=x2 -6x +8 .

a
(3,-1)

b
(-3, 1)

c
(-3,-1)

d
(3, 1)

1 Answer

5 votes

9514 1404 393

Answer:

a (3,-1)

Explanation:

The number that "completes the square" is the square of half the x-coefficient, (-6/2)^2 = 9. Rearranging the given function to include the square trinomial, we have ...

f(x) = x^2 -6x +9 -1 . . . . . . . here, we have 8 = 9 - 1

f(x) = (x -3)^2 -1 . . . . . . . . . . vertex form

Comparing this to the generic vertex form ...

f(x) = (x -h)^2 +k . . . . . . . vertex at (h, k)

we see that h=3 and k=-1.

The vertex is (h, k) = (3, -1).

13. Find the vertex of f(x)=x2 -6x +8 . a (3,-1) b (-3, 1) c (-3,-1) d (3, 1)-example-1
User Akash Karothiya
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories