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Model a hydrogen atom as a three-dimensional potential well with Uo = 0 in the region 0 < x a. 283 eV

b. 339 eV
c. 113 eV
d. 226 eV

User Mapad
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This question is incomplete, the complete question is;

Model a hydrogen atom as a three-dimensional potential well with U₀ = 0 in the region 0 < x < L, 0 < y < L and 0 < z < L, and infinite otherwise, with L = 1.0 × 10⁻¹⁰ m.

Which of the following is NOT one of the lowest three energy levels of an electron in this model?

a. 283 eV

b. 339 eV

c. 113 eV

d. 226 eV

Answer:

the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

Step-by-step explanation:

Given the data in the question;

Three dimension cube or particle in a cubic box

the energy value is given by;


E_{nx,ny,nz =
( n_x^2 + n_y^2 + n_z^2 ) × π²h"² / 2ml²

where h" = h/2π and h is Planck's constant ( 6.626 × 10⁻³⁴ m² kg / s )

m is mass of electron ( 9.1 × 10⁻³¹ kg )

l is length of side of box ( 1.0 × 10⁻¹⁰ m )

for ground level (
n_x = n_y = n_z = 1 )

so


( n_x^2 + n_y^2 + n_z^2 ) × π²h"² / 2ml²

since h" = h/2π


( n_x^2 + n_y^2 + n_z^2 ) × π²h² / (2π)²2ml²

so we substitute


E_{111 = ( 1² + 1² + 1² ) × [ π²( 6.626 × 10⁻³⁴ )² ] / [ (2π)² × 2 × 9.1 × 10⁻³¹ kg × ( 1.0 × 10⁻¹⁰)² ]


E_{111 = 3 × [ (4.333188779 × 10⁻⁶⁶) / ( 7.185072 × 10⁻⁴⁹ ) ]


E_{111 = 3 × [ 6.03082165 × 10⁻¹⁸ ]

Now, we know that electric charge = 1.602 x 10⁻¹⁹

so


E_{111 = 3 × [ (6.03082165 × 10⁻¹⁸) / (1.602 x 10⁻¹⁹) ]


E_{111 = 3 × [ 37.645578 ]


E_{111 = 112.9 ≈ 113 eV


E_{211 =
( n_x^2 + n_y^2 + n_z^2 ) × π²h² / (2π)²2ml²

we substitute


E_{211 = ( 1² + 1² + 2² ) × [ 37.645578 ]


E_{211 = 6 × [ 37.645578 ]


E_{211 = 225.87 ≈ 226 eV


E_{221 =
( n_x^2 + n_y^2 + n_z^2 ) × π²h² / (2π)²2ml²

we substitute


E_{221 = ( 2² + 2² + 1² ) × [ 37.645578 ]


E_{211 = 9 × [ 37.645578 ]


E_{211 = 338.8 ≈ 339 eV

Therefore, the lowest three energy are; 113 eV, 225 eV, and 339 eV.

Hence Option a) 283 eV is not among the three lowest energy

User Assaf Gamliel
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