Question

Find the zeros of y = x2 - 6x – 4 by completing the square.

O A. x = 3 + 5
B. X = +3
C. X = 3 + 13
D. x.-3113

Answer 1

√13 + 3 = x

-√13 + 3 = x

Explanation:

y = x² - 6x - 4

0 = x² - 6x - 4

0 + 13 = x² - 6x - 4 + 13

13 = x² - 6x + 9

13 = (x-3)²

±√13 = x-3

±√13 + 3 = x

√13 + 3 = x

-√13 + 3 = x